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A Scientific Discussion
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agreatguy6
Holy Chocobo


Member 682

Level 31.93

Mar 2006


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Old Aug 15, 2006, 05:17 PM #1 of 32
I totally agree with ORLY.
Of course E=mc^2 works both ways. It's an equation. It can be:
E/m=c^2
E/c2=m
E/mc2=0



I think.
Correct me if I'm wrong.

How ya doing, buddy?
agreatguy6
Holy Chocobo


Member 682

Level 31.93

Mar 2006


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Old Aug 15, 2006, 06:16 PM #2 of 32
I thought the rule was the ab=cd was equivalant to ab/cd=0.
Wasn't it? or was that something else.......

There's nowhere I can't reach.
agreatguy6
Holy Chocobo


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Level 31.93

Mar 2006


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Old Aug 15, 2006, 06:52 PM #3 of 32
Originally Posted by packrat
ab=cd => ab-cd=0
ab/cd=1


If you think about it, if ab is one quantity (for example x) and cd is the same quantity (x), then x/x=1.

Alternatively, if you subtract cd from ab, then you get x-x=0.


But, lets return to the thread title, with a related scientific discussion:

Quantum vacuum fluctuations.

Now, I read somewhere that there has been some success in observing these fluctuations. What does everyone think about the possibility of harvesting this phenomena by somehow separating the particles from their anti-particle pairs, and using them as a source of energy?
Ahh........
Thanks. Algebra student.
Not my fault.

This thing is sticky, and I don't like it. I don't appreciate it.
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