Exploding Garrmondo Weiner Interactive Swiss Army Penis

Exploding Garrmondo Weiner Interactive Swiss Army Penis (http://www.gamingforce.org/forums/index.php)
-   Pang's Violence Basement (http://www.gamingforce.org/forums/forumdisplay.php?f=13)
-   -   Science quiz (http://www.gamingforce.org/forums/showthread.php?t=26342)

katchum Oct 31, 2007 01:10 PM

Science quiz
 
I've had an assessment today and I'm impressed of the creativity they had in those tests.

Here's one:

Two barrels are filled with water and they have holes in it, which one is the right one?

http://two.xthost.info/katchum9/Test.JPG

I picked the first one, but I still don't know why and if its the right choice...

Gechmir Oct 31, 2007 01:22 PM

I say the bottom one. Notice that the furthest down hole is spraying the water further. I'd gather that to mean there's more pressure at the bottom than in the first one, in which the lower two holes seem to be "gushing" (exit with lower pressure) rather than "spraying" (exiting with high pressure).

katchum Oct 31, 2007 01:43 PM

Damn, damn, damn. You're right, I just figured it out.

Aargh.

Explanation:

The top hole has potential energy: rho. g. h. But has also pressure energy also rho. g. (H-h). H = length of the barrel and h = length from ground to the hole.
The bottom hole has the same energy because it has half the height/potential energy but double the pressure energy.

So basically they have the same energy! So they have to SPURT the same LENGTH of water. Which means you're right and I'm so dumb... But I got only 30 seconds to think about it, not ten minutes!


I still am not sure of the answer, can someone try it out?

I tried it out, and the experiment wasn't a success, because of too much friction. But I think it's safe to say that the bottom one is correct.

katchum Nov 2, 2007 10:08 AM

We have two similar cars on a 45 ° hill standing still. There is no friction between wheels and ground.

Now in the first car we place a fat guy of 200 kg.
In the second car we place a skinny guy of 25 kg.

Who has the highest acceleration when letting the cars roll?

i am good at jokes Nov 3, 2007 07:17 PM

I would say that the car with the fat guy in it would accelarate more since the mass is greater even though the resistance is the same.

katchum Nov 3, 2007 07:39 PM

Okay, it is a common mistake to say that the mass is greater => greater acceleration.

You have to take in account that the greater the mass, the greater the inertia of the material.

An example: with the same force it is more difficult to move a standing car than moving a bike.

So basically the greater mass makes the acceleration higher, but the greater mass has higer inertia. They cancel each other out so that leaves the answer to be:

They both have the same acceleration. (without the friction included)

Think about this too: when you are on your bike, would you rather be a fat guy or a slim guy to have the advantage of a high speed when riding off a mountain? I always thought that the fat guy would be faster but it's the slim guy! It has to do with friction. The fat guy has more friction on the wheels. That's also why cyclists want their bike to be light weight.

Edit: I was wrong, it's the fat guy who is the fastest, because he has more inertia and is less influenced by the wind. The friction of the wheels is less powerful as the friction of the wind.

Some of you could ask why cyclists put this added weight in the back wheel. It's just to reduce wind vortices with the plates and reduce turbulence of the wheel by adding weight.

New problem:

We have a rectangular magnet with North-South pole. You sprinkle neutral ferromagnetic particles in the middle of the magnet. What happens?

1) The particles spread over the entire magnet
2) The particles stay in the middle
3) The particles go to the North Pole
4) The particles go to the South Pole
5) The particles go to both poles

Dullenplain Nov 3, 2007 09:28 PM

http://img66.imageshack.us/img66/8216/magnet0873ob9.png

This happens.

katchum Nov 4, 2007 05:16 AM

We're not talking 2D/3D here. I'm talking about the alignment on the surface of the magnet. (Gravitational force is still stronger than magnetic force at those distances. The particles will fall down instead of floating in the air.)

CryHavoc Nov 4, 2007 09:01 PM

Both poles. And that drawing is of ferro-magnetic fillings scattered over a white sheet of paper resting on a magnet (or a magnet on it with the result photographed) Nothing floating in mid-air.

katchum Nov 5, 2007 04:05 AM

That's right, the flux is greatest at the poles and is zero on the mid section of the magnet's surface. All the flux is situated inside the magnet not outside the magnet. Answer 5.


New problem:

We have a wooden barrel with water. We place this 10 m long plastic thing of 1cm diameter in a little hole on top of the barrel and fill it with water.

The barrel can withstand 1kg/cm^2.

What will happen:

1) The barrel explodes
2) The water gushes out from the top
3) Nothing happens

http://two.xthost.info/katchum9/barrel.JPG

CryHavoc Nov 7, 2007 09:58 AM

Quote:

Originally Posted by katchum
We place this 10 m long plastic thing of 1cm diameter..

We place this 10 m long plastic thing of 1cm diame..

We place this 10 m long plastic thing of 1cm di..
We place this 10 m long plastic thing of 1cm..

We place this 10 m long plastic thing of 1cm diameter

Oh the science..

katchum Nov 7, 2007 04:50 PM

Yeah I know, when you say that on a job interview, they shoot you down... Let's say tube then.

YO PITTSBURGH MIKE HERE Nov 7, 2007 07:01 PM

Are we doing your homework here, by any chance?

CryHavoc Nov 7, 2007 08:40 PM

heh, even if we are it's sort of fun..

My guess, read:GUESS, is that nothing will happen, i don't think 0.10Pi x 0.5 is enough volume to cause more than a kg of pressure.

Giro0001 Nov 8, 2007 03:42 AM

Basically the original problem comes down to finding the velocity at which the water leaves the hole and then you simply use kinematics to figure out where each lands. Now the question comes down to finding the velocity at which it leaves the can. Unfortunately neither of those pictures are completely right. Lets pose the problem well.

We have a canister filled with water sitting on top of a table. The canister is filled with water to a height of H and there are holes on its side of equal size at intervals of h down from the top of the water.

Then v(velocity of water out from a hole h down from the top of the water) = sqrt(2gh)
You can use the correct application of Bernoulli's equation to get this interesting result.

Now we get v = 1.26 sqrt(h).

Now the problem is down to kinematics.

Find t using y and g.
0 = H - h - .5 (9.8) t^2
t = .45 sqrt(H-h)

Now use an equation of x using v and t and the fact that a_x=0
x = 0 + 1.26 sqrt(h) (.45 sqrt(H-h))
x = .569 sqrt(H h) -.569 h

So now as you can see it's a parabola. Graph it if you're interested in what it will look like. Remember to fix H though, H is the height of the water. h is your variable.

This equation is absolutely consistent with what we would expect. The very top where h = 0 has x = 0 and the very bottom when h = H , x = 0. Also I myself suspected that in the middle the distance x would actually reach it's maximum, which it in fact does.

CryHavoc Nov 8, 2007 09:09 AM

Well, Giro?

Does it explode?

DOES IT EXPLODE DAMMIT???

katchum Nov 8, 2007 12:24 PM

Hehe I understand, nice, nice! Thanks!

There is still one thing I don't understand: the velocity is the same when the hole gets bigger? This means only the mass flow gets higher with a bigger hole then...

Well, it explodes. I think. Because:

rho.g.h is the pressure and its: 1000kg/m^3 . 9.81m/s^2 . 10 m [Pa]

This would be the pressure at the bottom of the tube. And it's higher than 1 kg/cm^2. It's not the volume that makes the pressure, it's the height!


New problem:

Two cold glasses of -20 degrees °C are put in 90 °C water, which cracks?

The famous glasses problem. You have to take in account many, many factors!!!!

(mechanical strength, microscopic allignment of the glass, warmth transfer both in time and place, volumetric expansion)

http://two.xthost.info/katchum9/glasses.JPG

RacinReaver Nov 8, 2007 02:12 PM

Quote:

Originally Posted by Giro0001 (Post 528955)
Basically the original problem comes down to finding the velocity at which the water leaves the hole and then you simply use kinematics to figure out where each lands. Now the question comes down to finding the velocity at which it leaves the can. Unfortunately neither of those pictures are completely right. Lets pose the problem well.

We have a canister filled with water sitting on top of a table. The canister is filled with water to a height of H and there are holes on its side of equal size at intervals of h down from the top of the water.

Then v(velocity of water out from a hole h down from the top of the water) = sqrt(2gh)
You can use the correct application of Bernoulli's equation to get this interesting result.

Now we get v = 1.26 sqrt(h).

Now the problem is down to kinematics.

Find t using y and g.
0 = H - h - .5 (9.8) t^2
t = .45 sqrt(H-h)

Now use an equation of x using v and t and the fact that a_x=0
x = 0 + 1.26 sqrt(h) (.45 sqrt(H-h))
x = .569 sqrt(H h) -.569 h

So now as you can see it's a parabola. Graph it if you're interested in what it will look like. Remember to fix H though, H is the height of the water. h is your variable.

This equation is absolutely consistent with what we would expect. The very top where h = 0 has x = 0 and the very bottom when h = H , x = 0. Also I myself suspected that in the middle the distance x would actually reach it's maximum, which it in fact does.

Think about it another way, though. Say you put the canister on a really fucking tall table. So tall that the height of the hole in the can relative to the height of the table is insignificant. In that case, the difference in acceleration due to gravity once leaving the can shouldn't matter, and all that really matters is the initial velocity in the x direction.

Also, it should be easy to guess the trajectory will be a parabola because it's moving like a projectile under gravity. :p

As for the glasses, there's a turning point in which would crack. In the limit of the 90°C glass equaling the volume of the -20° glass, you shouldn't have any cracking since the volume of water trying to heat it up would be zero. In the limit of the -20°C glass being extremely thin, then there wouldn't be enough of a temperature gradient across it in order to produce thermal cracking no matter which situation we were in.

katchum Nov 8, 2007 04:02 PM

Right, the thicker the glass the higher chance of it breaking. But sometimes when I wash glasses with warm water, it's always the thin glass that breaks first. Here it is the fault on microscopical level, it is difficult to make strong surfaces when you make thin glass. The same goes for steel. A big steel tube is stronger than a thin steel tube. It has something to do with material science and all... agglomerates, crystals. I'm no expert really.

I'm a bit out of ideas...

Hey:

I've stuck a wooden pipe inside a man made hole in the center of a fan. Now when I push the wooden pipe really hard as stated in the following figure, what will happen visually? The fan is spinning at maximum speed.

1) Nothin happens
2) The fan will tip over and fall down

http://two.xthost.info/katchum10/Fan.JPG

RacinReaver Nov 8, 2007 07:53 PM

Quote:

Originally Posted by katchum (Post 529176)
It has something to do with material science and all... agglomerates, crystals. I'm no expert really.

I am.

Giro0001 Nov 8, 2007 09:37 PM

Quote:

Originally Posted by GRUN-2 (Post 529126)
Also, it should be easy to guess the trajectory will be a parabola because it's moving like a projectile under gravity. :p

Missed the point. When I mentioned the parabola I was speaking of the equation which is a function of the distance h from the top of the water at height H which represents the distance x from the canister where the stream of water hits the table. I didn't have the actual equation of the trajectory anywhere in my calculations.

Obviously when considering special conditions things may change. For example it changes slightly with variances in temperature. It has a great change with a temperature less than 0 C or greater than 100 C. Also the assumption made for Bernoulli's equation that atmospheric pressure is exactly the same at the top and the hole is not really true, it's actually slightly different. Many many things will change it. Certain things more than others. Other things are assumed, like that the table is relatively close to sea level (Not 10^30 miles above).


Now for the new problem it depends on how the force is applied. Clarify.

katchum Nov 9, 2007 03:47 AM

I was afraid it would make too much confusion.

I'll make a better problem now:

The man is turning clockwise around himself while holding a spinning wheel. Will this man rotate faster or slower or equal when the wheel isn't spinning at all? (while the man is using the same muscle power)

http://two.xthost.info/katchum10/manneke.JPG

Spoiler:
The gyroscope: the sum of all moments = w x L. w is the precession of the man. L is the rotation of the wheel. Both vectors are perpendicular to each other so the sum of all moments is perpendicular to w and L. This moment points to us. This means that the moment this man is applying to the stick is positive which will cause a certain precession w. If the wheel doesn't spin it won't cause this precession w and the man will turn slower with the same muscle power. I'm not entirely sure if I'm right, but you are Giro? Of course, I suspect your name has something to do with Gyroscope.


Another thing to think about, based on the same mechanics:

When you ride a bicycle and this bicycle is riding really fast. Then at some point you want to go to the right, what is the best thing to do?

1) Steer to the left
2) Steer to the right
3) Leaning out to the right
4) Leaning out to the left

Spoiler:
You need to steer to the left. Again: sum of M = w x L. L is the spinning wheel vector pointed to the left (while sitting on the bike). w is the precession = you lean out to the right. Precession vector is pointing forward. w x L is pointed upwards. So you have to apply a moment in counterclockwise motion on the steering wheel. The answer is steering to the left. Note that the only way to fall off your bike is to steer to the left or the right. Try it out! (if you don't include the moment between the two wheels and the ground...)

pyrrhus Nov 9, 2007 05:25 AM

*Makes note to self to read the above posts more thoroughly before commenting

katchum Nov 9, 2007 05:42 AM

Before I forget to post it, I'm on a roll here.

New Problem:

Everyone has gone to amusement parks. You know those little round boats floating in the river. And you trying not to get wet. Now when you get out of those boats you always walk on this rotating platform to get back to the exit in the center, all wet.

Ever thought of this? When you walk in a straight line to the center while the platform spins. Will you most likely fall to the left or the right?

http://two.xthost.info/katchum10/Radja%20River.JPG

pyrrhus Nov 9, 2007 05:59 AM

Won't that be dependant on the speed of walking towards the center and the speed of rotation?

@Katchum: been to Walibi recently? ;)

katchum Nov 9, 2007 07:39 AM

Yeah, Six Flags, it wasn't as fun as I expected... Bobbejaanland is better.

It doesn't depend on speed, either way you will fall, if you don't apply a reactional force to the ground. But which direction?!

RacinReaver Nov 10, 2007 03:05 AM

Quote:

Originally Posted by Giro0001 (Post 529362)
Missed the point. When I mentioned the parabola I was speaking of the equation which is a function of the distance h from the top of the water at height H which represents the distance x from the canister where the stream of water hits the table. I didn't have the actual equation of the trajectory anywhere in my calculations.

Whoops, my bad. I had seen a slightly different question a few days ago and assumed you were going at it the same way that we had approached that one.

Here's a good one I heard today.

Quote:

Your dog is running away from you at 2 m/s. Every time you whistle for him he doubles his speed. How many times will he hear you whistle?

katchum Nov 10, 2007 05:00 AM

How many times do I whistle, at which time intervals? Does echo reflection count? And how good is the dog's hearing?

RacinReaver Nov 10, 2007 10:23 AM

Dog can hear infinitely far, you can whistle as fast as you can in real life, and sound propagates infinitely far.

Just imagine as though you're on an infinite plane with nothing else there other than the dog and you.

slayer25k Nov 10, 2007 10:58 AM

I suppose it's about 8 times (edit: more like 7 times - depends on how you count ;P *valid excuse* ) the dog will hear you -

Since it doubles its speed every time, you'll have to count 2^x - and I tried it out...

It reaches sonic speed (which is 343 m/s under normal conditions) at about 2^8.45 (349.706)

That's my guess here... =(

RacinReaver Nov 13, 2007 03:43 AM

Nope, neither guess is correct.

pyrrhus Nov 13, 2007 03:55 AM

My guess would be 15
8 times till he's faster than the speed of sound at which time he'll overtake the sound waves of your previous whistles.

I'll assume he'll accelerate the same instance he hears the 8th whistle so he won't hear it twice.
Otherwise: 16

RacinReaver Nov 13, 2007 04:14 AM

Yeah, 15 is the answer. Everyone I've told that one to had that, "Man, that's a great question" reaction upon hearing the answer. I liked it because it had a good trick.

katchum Nov 13, 2007 11:44 AM

Hmm, intruiging.

When you use Doppler for a moving observer and standing source. You would see that the frequency will change.

This is the formular for an observer going away from the standing source:

f'=f(c-v)/c
c=sound velocity of source
v=velocity of observer moving away from source

Now for the dog problem we have something analogical:

f'=f(v-c)/v (not entirely sure)

v=velocity of the dog
c=velocity of the whistling sound

f'=1000(350-343)/350=20 Hz (approximately, assuming ideal temperature, pressure)

Too bad... the dog can hear this sound. So yeah 15 times. Unless the whistle is of a lower frequency, like the lower sol on a piano. ~400 Hz?

slayer25k Nov 14, 2007 12:38 PM

Quote:

Originally Posted by RacinReaver (Post 531725)
I liked it because it had a good trick.

Yeah - that's a nice trick; Too bad I haven't thought about it that way!

... I need to learn thinking twice ... the right way.

Lambert Dec 4, 2007 07:00 AM

Try with this one, less physics more logical thinking.

You have two strings whose only known property is that when you light one end of string it takes exactly 5 minutes or 10 minutes to burn. The rate at which the strings will burn is completely random and each string is different. How to measure with them 7,5 minutes ?

pyrrhus Dec 4, 2007 08:42 AM

Hmmm, interesting question.

I'd try to light both strings at the same time.
When the 5 minute string is burnt up, light the other string also at the other end. When that string is wasted, it should be exactly 7.5 minutes?

Lambert Dec 4, 2007 06:13 PM

Yes! The main idea was to light the string on both ends. Notice that it's even easier to burn the first one (lighting on both ends) which is 2,5mins, and then the second one on both ends, which gives 5 minutes, and a total of 7,5 minutes.

Next one:

Find the next object in the following sequence

o, t, t, f, f, s, s, e, n, t, ...

Good luck=D

katchum Dec 4, 2007 06:34 PM

No!!! I got those tests on my assessment, and I'm still having nightmares about them...

Spoiler:
To be honest I didn't find it. After thinking about it for 10 minutes I went mad and searched it up. But I'm not American you know, it's less obvious. But yeah, my IQ is only 120... As a mathematician you search for logical series and numerical things and when you finally see it you feel so stupid.

And I hope they don't put this one in the assessments because it's so unfair.


Another one they used was this:

d, o, m, i, s, o,...

I mean, that's just lame... people who don't play music can't possibly know this answer. I hate those consultants who make these tests.

i am good at jokes Dec 4, 2007 07:47 PM

Does o-f-f-s-e-t have anything to do with the answer?

Lambert Dec 5, 2007 04:20 AM

No, 'offset' has nothing to do with it. The answer is incredibly simple, but requires an idea.

btw I ensure you that the answer doesn't require any major knowledge.

Fluffykitten McGrundlepuss Dec 5, 2007 08:00 AM

Quote:

Originally Posted by Lambert (Post 544906)
Yes! The main idea was to light the string on both ends. Notice that it's even easier to burn the first one (lighting on both ends) which is 2,5mins, and then the second one on both ends, which gives 5 minutes, and a total of 7,5 minutes.

Next one:

Find the next object in the following sequence

o, t, t, f, f, s, s, e, n, t, ...

Good luck=D

e

That I got that as soon as I looked at it possibly says something about how my brain works.

Lambert Dec 5, 2007 11:59 AM

Excellent. Next one:

A man entered a pub. He sat at the bar and started a talk with the bartender. After a few minutes bartender said he had three sons. "How old are they?" asked the man at the bar. "Product of their ages is 72." replied bartender. The man started thinking. "I need more information" he said. "The total of their ages equals the number on the building which is opposite to my bar." said bartender. The man left, saw the number on the building and came back to the bar. "I still need more information" he said to the bartender. "The youngest one LOVES ice cream" said bartender. "Now I know the answer" said the man and smiled.

Yes.. what is the answer?

nazpyro Dec 5, 2007 12:33 PM

6, 6, and 2 yo?

Am I supposed to put how I thought about it?:
Prime factorization of 72: 2*2*2*3*3, so the three ages are combinations of the products of these. Take the possibilities, and add them:

18+2+2 = 22
6+6+2 = 14
9+4+2 = 15
12+3+2 = 17
8+3+3 = 14

If the building number across the street was 22, 17, or 15, the guy would be done, but he needed more info. So he learned there was a youngest: 6, 6, and 2.

Maico Dec 5, 2007 01:48 PM

Can you explain how you get to the answer, either Shin or Lambert? You just moved right on to the next question without any explanation. Some of us aren't geniuses. :(

Identity Crisis Dec 5, 2007 02:22 PM

Quote:

Originally Posted by Maico (Post 545512)
Can you explain how you get to the answer, either Shin or Lambert? You just moved right on to the next question without any explanation. Some of us aren't geniuses. :(

Answer Method:

One
Two
Three
Four
Five
Six
Seven
Eight
Nine
Ten
Eleven

Lambert Dec 6, 2007 04:50 AM

Nice=) I have another one:

Fish breeder Peter bought three ponds: one with silver carps, one with rudds and wone with both of them silver carps and rudds. Th previous owner put wrong all the signs (saying which spieces are in a corresponding pond). Now Peter would like to put them back in a correct order, but he don't want to fish to much fishes. He came up with an idea how to do that fishing only one fish at all. How? =)

pyrrhus Dec 6, 2007 05:48 AM

neat!

Spoiler:


Go fish one fish in the pond where the signs says "carps and rudds".

Assume you catch a rudd. You know all signs are wrong now, so the only option here is that there are only rudds in it. Place the sign rudd here.
Then replace the "rudd" sign with the "carp" sign. Finally replace the "carp" sign with the "carps and rudss" sign

Same logic if you get a carp out of it.




Next one:

Assume you're in front of two doors. One door leads to a treasure and the other one to instant death. The doors are guarded by twin brothers. One of the two brothers always speaks the truth and one of them always lies. Since they're identical twins you don't know which one is honest and which one a liar. Which question will you ask to know which door you should take? (to the treasure of course!)

Ballpark Frank Dec 6, 2007 05:55 AM

"Hey, shorty, what door does your brother day is the one leading to death?"

And you walk into the that one.

Additional Spam:
Duh.:
Oh, method: Alright, so by asking one twin to give you the answer from the other you know it will always be wrong. Why? Either way the answer goes through the liar, thus you can count on it being the wrong one.

katchum Dec 9, 2007 08:05 AM

This is a common warmth transfer question:

I'm making some tea and I have to add cold milk and sugar to it. So I boil the water and put it in my cup. But suddenly someone is calling me on the telephone (for approximately 10 minutes) and I don't want my cup of tea to be cold when I come back. What do I do?

1) poor the milk in it now
2) poor the milk in it after 10 minutes

If you know the answer, don't tell it too fast, let other people discuss first.

RacinReaver Dec 9, 2007 04:50 PM

Hmm, not sure about my answer.

Spoiler:
Put the milk in now. The same amount cold milk will always cool your tea by the same amount since your ratio of specific heats and whatnot isn't going to change, but things cooling don't cool at a linear rate, it's faster. So if the tea is very far away from ambient temperature, during ten minutes next to boiling it will lose more heat than thirty degrees over room temperature. Of course, I'd try to let the water sit in my mug for long enough that it heats the mug up a little, that way there'd be a bit of stored heat to keep the tea warm while the air's trying to cool it down. :p

katchum Dec 9, 2007 04:58 PM

Spoiler:
Right! But I don't understand the "warming up the mug thing". Why would you want to warm up the mug? That would cool down your tea. I would just add the milk directly so that the tea would be colder immediately. So the mug will be colder too, which means less warmth will be lost because of the temperature difference between mug and cold air.

Unless you mean that the mug is warmer than the fluid? This is only possible if the air has enough convection. => natural convection between air and fluid + fluid going to gas. And I think you're right because the fluid will cool down faster than the mug wall.

So 100% right. Great!

RacinReaver Dec 9, 2007 05:07 PM

Spoiler:
If you warm the mug up with the water, then when you add the milk to cool it off, the mug will actually try and heat the water back up.

I suppose in the end it wouldn't actually matter if you heated the mug with the water or not, since there should be about the same energy transfer both ways. Forgot when I was writing it that the water had to lose some of its own energy to heat the mug up. :p)

katchum Dec 9, 2007 05:10 PM

Spoiler:
Yeah it's more complex than that if you take in account convection and conduction of the mug wall and all. And we're not going into that area are we!

Fluffykitten McGrundlepuss Dec 11, 2007 06:43 AM

Spoiler:
If you left the tea bag in there for ten minutes the tea will be pretty horrible anyway. Why can't you take the tea cup and milk with you to the phone? Or even bring the phone back to the tea? Who actually still uses landlines?

A bit of common sense more often than not negates the need for scientists.

katchum Dec 11, 2007 04:07 PM

I'm not sure about this one:

I'm on earth now and see a big glass box (10 meter x 10 meter). Inside the box is vacuum.

Now someone inside the box (probably a robot) holds a feather in one hand and a metal ball in the other hand. He releases both materials. What happens?

Spoiler:
I just can't imagine a feather falling so fast. I just can't imagine it...

RacinReaver Dec 11, 2007 05:08 PM

Didn't they actually do this on the moon (or one of similar style)?

Spoiler:
They fall at the same rate because there's no air resistance. Gravity gives the same amount of pull downwards to both things, so they'll fall at the same rate.

packrat Dec 11, 2007 05:13 PM

Spoiler:
Actually it was a hammer and a feather.
YouTube Video

Hard to believe, but there you go, concrete video evidence.
Of course if you still don't want to believe it, in the related links there are several videos explaining how all the moon missions are hoaxes and this experiment never happened. ='D

katchum Dec 11, 2007 05:53 PM

We have a flame. (coming out of the cooking place with gas fuel)

You'll see a little bit of a blue color and much of the yellow color. Which one is the hottest part?

And if you have a flame, is it hotter at the bottom, at the top or in the middle?

When you warm up a metal in the dark, which color does it have? Red? Can it also turn into blue?

Fluffykitten McGrundlepuss Dec 12, 2007 11:44 AM

Spoiler:
Flames are tricky things and there's a bunch of factors that determine the hottest part. I think though that in a gas hob type flame, the hottest part is towards the middle or base, in this case the blue bit.

I don't think you can heat metal blue. I'm auditing an iron foundry at the moment and what comes out of their furnace is white to yellow. That's not much of a scientific answer though. :(

Locke Dec 12, 2007 03:17 PM

Quote:

Originally Posted by packrat (Post 549567)
Spoiler:
Actually it was a hammer and a feather.
YouTube Video

Hard to believe, but there you go, concrete video evidence.
Of course if you still don't want to believe it, in the related links there are several videos explaining how all the moon missions are hoaxes and this experiment never happened. ='D

To be specific, it was a geologist's hammer too iirc :P

packrat Dec 12, 2007 03:47 PM

Quote:

Originally Posted by katchum (Post 549586)
When you warm up a metal in the dark, which color does it have? Red? Can it also turn into blue?

Spoiler:
I believe this is more a characteristic of metals, but as you heat the metal up, yes it will start off looking red. Its been a while since I've looked into this, but I think the reason it is red is because when you add heat, the electrons of the atoms that make up the metal move to a higher energy level, and then drop down again into the lower energy states. The first electrons to step into the higher energy levels predominantly have larger orbital radii, and thus the photons released when they step back down tend to have a wavelength that JUST HAPPENS to be around the red region of the spectrum. When you add more heat energy to the metal, electrons in the lower energy orbitals start to emit photons as they step up and down, and since they come from smaller orbitals, the photons they emit are subsequently of a smaller wavelength. Unfortunately, you cannot see blue light being emitted from the heated metal because the electrons that would ordinarily do so (those in the lower energy levels) are merely joining the crowd of the rest of the spectrum, and the resultant light would at best be white. Following this line of reasoning (and I fear I'm making an ass of myself because I might be wrong) you can get different colors of light by heating different materials which have fewer electrons than those of metal, because the wavelengths of the photons first emitted will be from lower energy states, and thus a smaller wavelength.</essayquestion>

katchum Dec 12, 2007 03:58 PM

To be honest I don't know the answer this time... I always thought blue was warmer.

I also think the color you see is a function of the temperature. For a perfect black emittor. But yeah, metals are all but perfect black emittors.

YO PITTSBURGH MIKE HERE Dec 12, 2007 04:04 PM

The color of a flame can change due to a variety of things, one of the most prevalent being the material being burned. Adding certain chemicals to a flame can radically alter its color. I'm sure temperature has an influence, but it certainly isn't the sole factor.

packrat Dec 12, 2007 04:31 PM

Spoiler:
The rules for black body emissions definitely operate separately from diffusion flames. Otherwise, your typical candle flame would be burning at a couple thousand degrees kelvin, rather than a couple hundred.

As I understand, scientists are just now coming to grips with what makes flame act the way it does. I've been told since I was a wee-lad that blue flames are hotter than the rest, though I have also never heard a satisfactory explanation for why.

I would imagine that the areas of most perfect combustion will be the hottest, and subsequently this will be the areas where the mixture of oxygen and fuel are most ideal. This is of course at the bottom of the flame, since as hot air goes up oxygen-rich air from around the base is whisked in to replenish what was displaced. This air has the highest concentrations of oxygen, so fuel burns at the highest efficiencies in this region.
The color of the flame aside, I reason that the regions closest to the base of combustion are the hottest.

katchum Dec 14, 2007 06:33 AM

Two glasses of water are at the same temperature. In one of them you dissolve 2 spoons of salt.

Then you throw in both of the glasses some ice cubes. In which glass will the ice cubes melt the fastest?

Fluffykitten McGrundlepuss Dec 14, 2007 07:47 AM

Spoiler:
Adding salt to water lowers the freezing point, therefore the cube in the salty water will dissolve faster.


I've got one. If the time is 1:11, how long in minutes and seconds will it be until the hands cross again on a standard, analogue clock?

katchum Dec 14, 2007 08:30 AM

I'm not sure about that. It seems that the water will be colder in the glass with salt. I'm going to do the experiment myself, as I don't know the answer. :eagletear:

I believe you, but I'm also sceptical.

And: one hour and six minutes? I don't understand the question really. Otherwise it also could be one minute.

EDIT: I CHECKED IT!!!!

The glass with salt water melts SLOWER!!!! Anyone who can give an explanation?

RacinReaver Dec 14, 2007 05:41 PM

I think the question is posed incorrectly. I looked around a bit, and found this slightly analogous situation. It would have to be the same weight in both cups. One containing, say, 1 kg of water, and the other containing of 1 kg of water + salt.

Quote:

Freezing point of salt water « The Official MartinZ Blog

Does water boil faster if you put salt in the water?

Yes and no. If you look at how fast water boils when you add a small amount of salt to it, such as when cooking your noodles, the change is insignificant between pure water and the salted water. However, if you take two identical pots and add one gallon of pure water to one pot and one gallon of 20 percent salt water to the other and heat the two pots on identical stoves, the pot containing the salt water will come to a boil first. Surprised?

To truly answer the question, one must look at what it takes to boil a container of water.

The time it takes a bucket of liquid to boil is controlled by essentially three things. The first is how much heat or energy you put into the bucket. The second is how fast the temperature rises in response to the heat input (the liquid’s heat capacity), and the third is the boiling point of the liquid. Assuming that we can control our stoves and add the same amount of energy to each pot, this variable becomes insignificant.

The boiling point of water does rise if you add salt to it, but only by about 2°C (4°F) to 102°C (216°F). Remember, water boils at 100°C (212°F). This is an insignificant change for adding such a large amount of salt. For you science nerds out there, the boiling point increase is calculated using the “ebullioscopic” constant of water. This leads us to the important variable, how fast water or salt water heats up, or the solution’s heat capacity.

The heat capacity of water is very high. What this means is that it takes a lot of energy to raise the temperature of water 1°C; in fact, the calorie is defined as the amount of energy that it takes to heat one gram of water to 1°C. Not to digress, but the high heat capacity of water is good, especially if you live on a planet where two-thirds of the surface is covered by water - it helps regulate the global temperature.

Now back to the question. If you look at the heat capacity of salt water, you will find that it is less than pure water. In other words, it takes less energy to raise the temperature of the salt water 1°C than pure water. This means that the salt water heats up faster and eventually gets to its boiling point first.

Why does salt water have a lower heat capacity? If you look at 100 grams of pure water, it contains 100 grams of water, but 100 grams of 20 percent salt water only contains 80 grams of water. The other 20 grams is the dissolved salt. The heat capacity of dissolved salt is almost zero when compared to the high heat capacity of water. This means that the heat capacity of a 20-percent salt solution is 80 percent that of pure water. Twenty percent salt water will heat up almost 25 percent faster than pure water and will win the speed race to the boiling point.

Please note that this will not hold true if you take two identical pots containing one gallon of water each and add the salt to one pot because then the volume of liquid in the salted pot will be greater than the one gallon starting point.

katchum Dec 14, 2007 05:47 PM

I'm sorry but you're looking at the wrong direction. I'll explain the answer.

The salt in the water wouldn't make any huge difference on the temperature, so don't search in that area.

What you have to think about is convection!

When you put an ice cube in the salt water, the cold water stays above and the warm water stays underneath, because salty water has a higher density! => ice cube doesn't melt fast.

When you put an ice cube in normal water, the cold water goes down and the warm water rises up => ice cube melts faster.

RacinReaver Dec 14, 2007 05:59 PM

Actually the convection wouldn't matter, I think what would matter is in salt water more of the ice cube would float over the top of the surface (less would be submerged), so less water touching it means it melts slower. I think for normal water it's something like 4/5 of the ice cube would be submerged (actually just had that value on the final I took yesterday), so when it's salt water, maybe only 3/5 would be submerged. Since the side of the ice cube touching the water would transfer heat faster than the side touching the air, the one with more ice in the water would melt faster.

I think the convection currents within the water itself should be approximately the same between the two.

pyrrhus Dec 15, 2007 07:06 AM

I found this explanation satisfying:

General Chemistry Online: FAQ: Solutions: Why can adding salt to ice water make the ice melt slower?

katchum Dec 15, 2007 07:46 AM

No pyrrhus, that experiment is done while stirring! In my case I just put the ice cube in the salt water, without stirring.

See:

"Watch how the temperature of the ice water falls after the initial addition of salt. What does a plot of temperature vs. time look like? (Stir constantly and completely!) "

I still think it's convection. Because you can easily imagine that this ice water layer around the ice cube will be motionless, therefore it gives isolation around the ice cube. (when put in the salt water)

In normal water there is natural convection, so no isolation around the ice cube.

When you do the experiment yourself you can even SEE it! There are these little transparant lines flowing all over...

Here is my reference, it's in flemish though. Pyrrhus will confirm it's true!:

NWO - De Quiz van 2000

Quote: "In het bekertje met zoetwater smelt het ijs. Het koud smeltwater is zwaarder dan het oorspronkelijke water, zodat het naar de bodem zakt. Het warme water stijgt juist op, waardoor er weer ijs zal smelten. Kortom, er treedt circulatie op in het glas. Er wordt steeds warm water aangevoerd dat het ijs snel doet smelten.

Anders gaat het toe in het glas met zout water. Daar is het smeltwater van het ijsblokje zoet en het omgevingswater is zout. Zoetwater is veel lichter dan zout water. Het koude zoetwater zal niet zakken en het ijsklontje blijft omgeven door het koude smeltwater. Er treedt geen convectie op en daarom zal het ijs in het glas met het zoute water veel langzamer smelten."



I'll post some more nice questions from that site next time.

RacinReaver Dec 15, 2007 03:23 PM

Shouldn't there be even more currents in the salt water one since you'll be getting a gradient in the concentration of salt with less salt surrounding the melting ice cube and more salt towards the bottom of the glass?

katchum Dec 15, 2007 05:32 PM

You mean like diffusion? There is, but the effect of density is bigger, I think.

RacinReaver Dec 15, 2007 07:21 PM

Hmm, looking up the density of seawater (~3.5% salinity) the density is 1.025g/mL. That's 35g of salt in 1 kg of water. I figure if we put two heaping tablespoons of water we'd have maybe 14% salinity, so just guessing that makes it around 1.1g/mL. So, yeah, only 10% more of the ice cube would be poking out of the water. So instead of 80% of the ice cube being underwater it would be closer to 72% touching the water.

I still think it could go either way. :(

pyrrhus Dec 16, 2007 06:15 AM

It's some time ago, but I know I've learned somewhere that if there's a high difference in temperature or salinity of two solutions touching each other, diffusion is more difficult, unless you of course go stir the solution.

So diffusion won't play that much here.

katchum Dec 16, 2007 06:28 AM

Since nobody answers Shin's question I'll post another one.

What's the coldest: -40°C or -40°F?

YO PITTSBURGH MIKE HERE Dec 16, 2007 12:16 PM

They're about the same, as Fahrenheit and Celsius coincide around that point.

katchum Dec 16, 2007 02:53 PM

What happens when you cook an egg at 65° C for 15 minutes?

YO PITTSBURGH MIKE HERE Dec 16, 2007 04:12 PM

Sounds like a soft boiled egg, to me.

katchum Dec 16, 2007 04:23 PM

Nope! There is something spectacular going on in the egg.

knkwzrd Dec 16, 2007 04:32 PM

The egg won't harden, but it will become safe to eat.

I don't know why you'd want that, though.

YO PITTSBURGH MIKE HERE Dec 16, 2007 04:33 PM

It's very useful for Rocky reenactments.

katchum Dec 17, 2007 04:24 PM

Nope, that yellow thing inside the egg becomes hard and the egg white stays fluid. Try it yourself. Use a thermocouple.

Why we'd want that? For science's sake!


All times are GMT -5. The time now is 04:35 PM.

Powered by vBulletin® Version 3.8.9
Copyright ©2000 - 2025, vBulletin Solutions, Inc.